How do you solve #4x+3y=-7# and #5x-2y=-26#?

Question

2355 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T21:54:47

Combine the equations to eliminate #y# and solve for #x#. Then substitute the value found for #x# and solve for #y# to find:

#{ (x = -4), (y = 3) :}#

Multiply the first equation by #2# and the second by #3# to get:

#{ (8x+6y = -14), (15x-6y=-78) :}#

Add these two equations together to get:

#23x = -92#

Divide both sides by #23# to get:

#x = -4#

Substitute this value of #x# in the first given equation to get:

#-7 = 4(-4)+3y = -16+3y#

Add #16# to both ends and transpose to get:

#3y = 9#

Divide both sides by #3# to get:

#y = 3#