Question

How do you solve 4x+6y=12 for x?

Answer 1

See the entire solution process below:

Explanation:

First, subtract `color(red)(6y)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`4x + 6y - color(red)(6y) = 12 - color(red)(6y)`

`4x + 0 = 12 - 6y`

`4x = 12 - 6y`

Now, divide each side by `color(red)(4)` to solve for `x` while keeping the equation balanced:

`(4x)/color(red)(4) = (12 - 6y)/color(red)(4)`

`(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = (12 - 6y)/4`

`x = (12 - 6y)/4`

Or

`x = 12/4 - 6/4y`

`x = 3 - (2 xx 3)/(2 xx 2)y`

`x = 3 - (color(red)(cancel(color(black)(2))) xx 3)/(color(red)(cancel(color(black)(2))) xx 2)y`

`x = 3 - 3/2y`