How do you solve 4x + y = 44x+y=4 and y = 4 - 4xy=44x using substitution?

1 Answer
May 12, 2017

Both xx and yy equal all real numbers

Explanation:

If y=4-4xy=44x, then we can replace the color(blue)(y)y in 4x+color(blue)(y)=44x+y=4 with 4-4x44x:

4x+(4-4x)=44x+(44x)=4

Solve for xx

4x+4-4x=44x+44x=4

subtract 44 on both sides

4x-4x=04x4x=0

0x=00x=0

x=oox=
color(white)(0)0

Let's try solving for yy now.

We need to isolate xx:

4x+y=44x+y=4

4x=4-y4x=4y

x=(4-y)/4x=4y4

Now, let's replace color(blue)(x)x with (4-y)/44y4 in y=4-4color(blue)(x)y=44x

y=4-cancel(4)(color(black)((4-y)/cancel(4)))

y=4-4-y

0y=0

y=oo

The reason x and y both equal oo is that any number, multiplied by 0, equals 0. So, x can equal -500, 8/19, or 9.01xx10^13, and still equal 0, thus making the equation true. The same fact also applies for y.

Both x and y equal all real numbers