How do you solve $4y = 11 - 3x$ and $3x + 2y = -5$ ?

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Answer 1 · 2018-06-18T06:18:55

The solution is ${(x=-7),(y=8):}$

Solve as follows

${(4y=11-3x),(3x+2y=-5):}$

Rewrite the equations as

${(3x=11-4y),(3x=-5-2y):}$

Therefore,

$11-4y=-5-2y$

$<=>$ , $4y-2y=11+5$

$<=>$ , $2y=16$

$<=>$ , $y=16/2=8$

$3x=11-4*8=11-32=-21$

$<=>$ , $x=-21/3=-7$

How do you solve 4y = 11 - 3x4y = 11 - 3x and 3x + 2y = -53x + 2y = -5?