How do you solve #4y = 11 - 3x# and #3x + 2y = -5#?

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Answer 1 · 2018-06-18T06:18:55

The solution is #{(x=-7),(y=8):}#

Solve as follows

#{(4y=11-3x),(3x+2y=-5):}#

Rewrite the equations as

#{(3x=11-4y),(3x=-5-2y):}#

Therefore,

#11-4y=-5-2y#

#<=>#, #4y-2y=11+5#

#<=>#, #2y=16#

#<=>#, #y=16/2=8#

#3x=11-4*8=11-32=-21#

#<=>#, #x=-21/3=-7#