How do you solve #4y - \frac { 2y } { 5} = 36#?

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Answer 1 · 2018-04-18T16:22:35

#y = 10#

#4y - \frac { 2y } { 5} = 36#

#(4yxx5)/5- (2y)/5 =36#

#(20y - 2y)/5 =36#

#(18y)/5 = 36#

#18y = 5 xx 36#

#18y = 180#

#y = 180/18#

#y = 10#