How do you solve $5(10^y)=1+2(10^y)$ ?

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Answer 1 · 2018-05-10T17:33:14

I tried this:

Let us write it as:

$5(10^y)-2(10^y)=1$

collect:

$(10^y)[5-2]=1$

$(10^y)*3=1$

$10^y=1/3$

take the log in base $10$ of both sides:

$log_(10)(10^y)=log_(10)(1/3)$

giving:

$y==log_(10)(1/3)=-0.477121$

How do you solve 5(10^y)=1+2(10^y)5(10^y)=1+2(10^y)?