How do you solve #-5*2^(-7n-7)+5=-66#?

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Answer 1 · 2017-03-04T05:43:15

#n=-1-root(7) (log_2 (71/5))#

You would subtract 5 and divide all by -5:

#-5*2^(-7n-7)=-71#

#2^(-7n-7)=71/5#

then it is

#-7n-7=log_2 (71/5)#

#-7n=7+log_2 (71/5)#

#n=-1-1/7log_2 (71/5)#

#n=-1-root(7) (log_2 (71/5))#