How do you solve #5/2t-t=3.3/2t#?

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Answer 1 · 2017-08-06T13:29:28

There is either something wrong with the question of #t=0#

Note that #-t# is the same as #-(2t)/2#

Write as:

#(5t)/2-(2t)/2=(3.3t)/2#

As the denominators are all the same write as:

#" "5t-2t=3.3t larr" This is equally true"#

#3t=3.3t#

#0.3t=0" "=>" "t=0#