How do you solve #5^(2x+2)=1/625#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Cesareo R. Aug 25, 2016 #x = -3# Explanation: #5^(2x+2)=1/625 = 1/5^4 = 5^(-4)# so #2x+2=-4#. Solving for #x# #x = -3# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2931 views around the world You can reuse this answer Creative Commons License