Question

How do you solve `(5-x)^2(x-13/2)<0`?

Answer 1

`x in (-oo,13/2)-{5}`

Explanation:

Observe that `AAx in RR, (5-x)^2>=0,` equality holds `iff x=5.`

Hence, `(5-x)^2(x-13/2)<0 iff (x-13/2)<0 & x!=5 iff x<13/2, x!=5`.

This can be put as `x in (-oo,13/2)-{5}`