How do you solve #5+x/4=1#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer EZ as pi Sep 14, 2016 #x = -16# Explanation: Isolate the term in #x# on the left side: #5-5 + x/4 =1-5# #x/4 = -4" "larr# multiply both sides by 4 #cancel4/1xx x/cancel4 = -4 xx4# #x = -16# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 8366 views around the world You can reuse this answer Creative Commons License