How do you solve #5(x+4)=4x+15#?

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Answer 1 · 2018-05-23T00:43:32

#x = -5#

First, use the distributive property shown below to simplify #5(x+4)#:
cdn.virtualnerd.com

Following this image, we know that:
#5(x+4) = (5 * x) + (5 * 4) = 5x + 20#

Put that back into the equation:
#5x + 20 = 4x + 15#

Now subtract #color(blue)(4x)# from both sides of the equation:
#5x + 20 quadcolor(blue)(-quad4x) = 15 quadcolor(blue)(-quad15)#

#x + 20 = 15#

Now subtract #color(blue)20# from both sides of the equation:
#x + 20 quadcolor(blue)(-quad20) = 15 quadcolor(blue)(-quad20)#

#x = -5#

Hope this helps!