How do you solve $5^{x} = 45$ $5^x=45$ ?

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Answer 1 · 2016-10-17T00:18:27

$x = 2.365$ $x=2.365$

$5^{x} = 45$ $5^x=45$

${log 5}^{x} = log 45 a a a$ $log5^x=log45color(white)(aaa)$ Take the log of both sides

$x log 5 = log 45 a a a$ $xlog5=log45color(white)(aaa)$ Use the log rule ${log x}^{a} = a log x$ $logx^a=alogx$

$\frac{x log 5}{log 5} = \frac{log 45}{log 5} a a a$ $(xlog5)/log5=log45/log5color(white)(aaa)$ Divide both sides by log5

$x = 2.365$ $x=2.365$

How do you solve 5x=455^x=45?