Question

How do you solve `5^x=45`?

Answer 1

`x=2.365`

Explanation:

`5^x=45`

`log5^x=log45color(white)(aaa)`Take the log of both sides

`xlog5=log45color(white)(aaa)`Use the log rule `logx^a=alogx`

`(xlog5)/log5=log45/log5color(white)(aaa)`Divide both sides by log5

`x=2.365`