How do you solve #5u - 31\leq - 2( 5- 4u )#?

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Answer 1 · 2018-04-11T16:35:02

#-7 ≤ u#

Expand on the right side so you get

#-2xx5 = -10" "# and #" "-2x-4u = 8u#

This gives you

#5u-31≤-10 + 8u#

Next, you want to take away #5u# from both sides and add #10# to both sides. This gives

#-21≤3u#

You can then divide both sides by #3# to get #u#, so

#-21/3 ≤ u#

#- 7 <= u#