How do you solve #5x - 1/2y = 24# and #3x - 2/3y = 41/3#?
1 Answer
Explanation:
You can solve this system of equations by multiplication.
Start by rewriting your two equations so that you can work without denominators.
#{(10x - y = 48), (9x - 2y = 41):}#
Notice that you can multiply the first equation by
#10x - y = 48 | * (-2)#
#-20x + 2y = - 96#
You can now add the two equations to cancel the
#-20x + color(red)(cancel(color(black)(2y))) + 9x - color(red)(cancel(color(black)(2y))) = -96 + 41#
#-11x = -55 implies x= ((-55))/((-11)) = color(green)(5)#
Use the value of
#10 * 5 - y = 48#
#y = 50 - 48 = color(green)(2)#
The two solutions to this system of equations are
#{(x = 5), (y = 2) :}#