How do you solve #-5x - 4y = -48# and #-3x + 2y = 2 # using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer ali ergin Mar 12, 2016 #x=4# Explanation: #-5x-4y=-48" (1)"# #-3x+2y=2 " "2y=2+3x " "color(green)(2*)2y=color(green)(2*)(2+3x)# #color(red)(4y=4+6x)# #"use (1)"# #-5x-color(red)((4+6x))=-48# #-5x-4-6x=-48# #-11x=-48+4# #-11x=-44# #x=44/11# #x=4# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1124 views around the world You can reuse this answer Creative Commons License