How do you solve 5x \leq 21+ 2x5x≤21+2x? Algebra Linear Inequalities and Absolute Value Inequalities with Addition and Subtraction 1 Answer Sebby · Stefan V. May 15, 2018 x <= 7x≤7 Explanation: 5x <= 21 + 2x5x≤21+2x Subtract 2x2x from each side 3x <= 213x≤21 Divide both sides by 33 x<= 7x≤7 Answer link Related questions Does the inequality sign change when you are you subtracting? How do you solve inequalities with addition and subtraction? How do you solve inequalities with fractions? How do you solve 15 + g \ge -6015+g≥−60? How do you graph x + 65 < 100x+65<100? How do you solve the inequality 5 + t \ge \frac{3}{4}5+t≥34? How do you graph the inequality x - 1 > -10x−1>−10 on a number line? Why do you not change the inequality sign when you are adding or subtracting? What's the result when you raise a number to the zero power? How do you solve x+ 3 < 2x+3<2? See all questions in Inequalities with Addition and Subtraction Impact of this question 1432 views around the world You can reuse this answer Creative Commons License