Question

How do you solve `6*4^(9x+1)=21`?

Answer 1

`x~=-0.01070`

Explanation:

`6*4^(9x+1)=21`

`4^(9x+1)=21/6=7/2`

`4^(9x) xx 4 =7/2`

`4^(9x) = 7/8`

`9xlog4 = log(7/8) = log7 - log8`

`9x = (log7-log8)/log4`

`9x ~= -0.09632`

`x~= -0.01070`