How do you solve #6/n=3/0.51#?

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Answer 1 · 2017-02-17T11:07:39

#n=1.02#

This does work!

Turn everything upside down giving:

#n/6=0.51/3#

Don't like decimals so lets get rid of them

#color(green)(n/6=0.51/3color(red)(xx1)" "->" "n/6=0.51/3color(red)(xx100/100))#

#color(green)(" "n/6=51/300)#

Multiply both sides by #color(red)(6)#

#" "color(green)(n/6color(red)(xx6) =51/300color(red)(xx6))#

#" "color(green)(nxx cancel(6/6)=51/(cancel(3)^1xx100)xxcancel(6)^2)#

#" "color(green)(n=102/100=1.02#