How do you solve $6 (x + 3) = 3 (x - 6)$ $6(x+3) = 3(x - 6)$ ?

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Answer 1 · 2015-10-27T20:55:38

$x = - 12$ $x=-12$

First multiply out the brackets to get

$6 x + 18 = 3 x - 18$ $6x+18=3x-18$

Now isolate all the x terms on 1 side of the equation

$6 x - 3 x = - 18 - 18$ $6x-3x=-18-18$

$therefore 3x=-36$

$therefore x=-12$

How do you solve 6(x+3) = 3(x - 6)6(x+3)=3(x−6)6(x+3) = 3(x - 6)?