How do you solve $6 (x - 3) - 5 x \geq 15$ $6(x-3) - 5x >= 15$ ?

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How do you solve $6 (x - 3) - 5 x \geq 15$ $6(x-3) - 5x >= 15$ ?

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Answer 1 · 2016-03-17T10:12:38

x ≥ 33

Explanation:

First , distribute bracket.

hence : 6x - 18 -5x ≥ 15

now collect like terms : x - 18 ≥ 15

Finally add 18 to both sides: x - 18 + 18 ≥ 15 + 18

$\Rightarrow x \geq 33$ $rArr x ≥ 33$

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How do you solve $6 (x - 3) - 5 x \geq 15$ $6(x-3) - 5x >= 15$ ?

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