How do you solve #6x^2 + 24x = 0 #? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer ali ergin Mar 7, 2018 #"the answer is {-4,0}"# Explanation: #6x^2+24x=0# #"Rearrange the equation like the fallowing."# #6x^2=-24x# #"Divide the both sides of equation by 6."# #cancel(6)x^2=-cancel(24)x# #x^2=-4x# #"Divide the both sides of equation by 'x'."# #cancel(x)^2=-4cancel(x)# #x=-4# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 5982 views around the world You can reuse this answer Creative Commons License