How do you solve #6x + y = 23# and #x + 5y = 28#?

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Answer 1 · 2016-06-25T13:36:18

The solution for the system of equations is :
#color(green)(x = 3 , y=5#

#color(blue)(6x) + y = 23#...............equation #(1)#

#x + 5y = 28# , multiplying by #6:#

#color(blue)(6x) + 30y = 168#........equation #(2)#

Subtracting equation #1# from #2:#

#cancelcolor(blue)(6x) + 30y = 168#
#-cancelcolor(blue)(6x) - y = -23#

#29y= 145#

#y = 145/29#

#color(green)(y = 5 #

Finding #x# from equation #2:#

#x + 5y = 28#

#x = 28 - 5y #

#x = 28 - 5 xx 5 #

#x = 28 - 25 #

#color(green)(x = 3#