How do you solve $7/4z - 1/6 = 17/6 + 3/4z$ ?

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Answer 1 · 2018-04-27T05:34:07

$color(blue)(z = 3$

$(7/4)z - 1/6 = 17 / 6 + (3/4)z$

$(7/4)z - (3/4)z = 17 / 6 + 1/6, " bringing like terms together"$

$((7 - 3) / 4) z = (17 + 1) / 6, " combining terms using common denominator"$

$(cancel4/cancel4)z = (cancel(18)^color(red)(3) /cancel 6)$

$color(blue)(z = 3$

How do you solve 7/4z - 1/6 = 17/6 + 3/4z7/4z - 1/6 = 17/6 + 3/4z?