Question

How do you solve `7( k + 2) + 5\geq 5`?

Answer 1

`k≥-2`

Explanation:

As with any equation, expanding the brackets is always what we do first.

`7(k+2) +5≥5`

-> `7(k+2)`

`7xxk=7k`

`7xx2=14`

Removing the brackets and replacing it with these values.

`7k+14+5 ≥5`

This can collect like terms of the 14+5, as they are on the same side of the equation and are both a constant.

`7k+19≥5`

As to solve any equation we want to isolate `x` to make it be on its own, therefore we need to `-19` to cancel out the `+19`, remember we do this to both sides.

`7k+19≥5 -> 7k≥-14`

as `5-19=-14` it changes to `7k≥-14`

Now to solve an equation like this, we divide the value by how much of the term we have

`therefore` `k=-14/7=-2`

Remember to always put the sign back in...

`k=-2`

-> `k≥-2`