How do you solve #7(x+4)>0#?

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Answer 1 · 2017-07-21T02:27:04

See a solution process below:

Step 1) Divide each side of the inequality by #color(red)(7)# to eliminate the parenthesis while keeping the inequality balanced:

#(7(x + 4))/color(red)(7) > 0/color(red)(7)#

#(color(red)(cancel(color(black)(7)))(x + 4))/cancel(color(red)(7)) > 0#

#x + 4 > 0#

Step 2) Subtract #color(red)(4)# from each side of the inequality to solve for #x# while keeping the inequality balanced:

#x + 4 - color(red)(4) > 0 - color(red)(4)#

#x + 0 > -4#

#x > -4#