Question

How do you solve `8+ 10+ x \leq 51`?

Answer 1

`18+x≤51`

`x≤51-18`

`x≤33`

Explanation:

What you need to do is isolate the variable (`x` in this case) on one side of this inequality.

Start by adding up `8` and `10` to make `18`, then move that over to the other side of the equation to make it `-18` (negative `18`). Add that to `51` and you will get `33`.

Another way to make sense of this is to just subtract `18` from each side instead of moving it around. Regardless, you'll get the same answer.

Final answer:

`x≤33`