How do you solve 8(2f - 2) = 7(3f + 2) 8(2f−2)=7(3f+2)?

1 Answer
Jill L.
Apr 20, 2017

The final answer is -6=f−6=f.

Explanation:

8(2f-2)=7(3f+2)8(2f−2)=7(3f+2)

(8*2f)+(8*-2)=(7*3f)+(7*2)->(8⋅2f)+(8⋅−2)=(7⋅3f)+(7⋅2)→ Expand both sides by using the Distributive Property.

16f-16=21f+1416f−16=21f+14

cancelcolor(red)(16f)-16cancelcolor(red)(-16f)=cancel(21fcolor(red)(-16f))5f+14-> Subtract 16f from both sides.

cancel(-16color(blue)(-14))-30=5fcancelcolor(blue)(+14)cancelcolor(blue)(-14)-> Subtract 14 from both sides.

cancel(-30color(green)(/5))-6=cancelcolor(green)(5)fcancelcolor(green)(/5)-> Divide both sides by 5.

-6=f-> Final answer!

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