How do you solve #8(2w-6) + 4 (-1 - 5w)= 0#?

Question

2464 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-26T14:58:30

# w = - 13#

#8 ( 2w - 6) + 4 ( - 1 - 5w) = 0#

#8 * ( 2w) + 8 * ( - 6) + 4 * ( - 1) + 4 * ( - 5w) = 0#

# 16w - 48 - 4 - 20 w = 0#

# (16w - 20w) - 4 - 48 = 0#

# - 4w - 52 = 0#

# - 4w = 52#

# w = 52 / (-4)#

# w = - 13#