How do you solve #8x-9y=32.5# and #7y-2x=-10.5# using substitution?

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Answer 1 · 2017-09-09T10:35:49

Solution: # x= 3.5 ,y = -0.5#

# 8x-9y= 32.5#(1) , # 7y-2x= -10.5#(2) , From equation (2)

we get #2x= 7y+10.5 or x= 3.5y + 5.25 # (3), Putting

#x= 3.5y + 5.25 # in equation (1) we get,

#8( 3.5y + 5.25) -9y = 32.5 or 28y+42-9y=32.5# or

#19y = 32.5-42 or 19 y= -9.5 or y = -0.5 # Putting

#y = -0.5 # in equation (3) we get, #x= 3.5 *(-0.5)+5.25# or

#x=3.5 :.# Solution: # x= 3.5 ,y = -0.5# [Ans]