How do you solve $8 y = - 16$ $8y = -16$ and $- 10 x + 8 y = 64$ $-10x + 8y = 64$ ?

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How do you solve $8 y = - 16$ $8y = -16$ and $- 10 x + 8 y = 64$ $-10x + 8y = 64$ ?

1 Answer

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Answer 1 · 2016-07-29T12:12:17

$x = - 8$ $x=-8$
$y = - 2$ $y=-2$

Explanation:

By putting $8 y = - 16$ $8y=-16$ in the equation $- 10 x + 8 y = 64$ $-10x+8y=64$
we get
$- 10 x - 16 = 64$ $-10x-16=64$
or
$- 10 x = 64 + 16$ $-10x=64+16$
or
$- 10 x = 80$ $-10x=80$
or
$x = - \frac{80}{10}$ $x=-80/10$
or
$x = - 8$ $x=-8$ ========Ans $1$ $1$

$8 y = - 16$ $8y=-16$
or
$y = - \frac{16}{8}$ $y=-16/8$
or
$y = - 2$ $y=-2$ ========Ans $2$ $2$

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How do you solve $8 y = - 16$ $8y = -16$ and $- 10 x + 8 y = 64$ $-10x + 8y = 64$ ?

1 Answer

Explanation:

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How do you solve $8 y = - 16$ $8y = -16$ and $- 10 x + 8 y = 64$ $-10x + 8y = 64$ ?