How do you solve $\frac{9}{k} - 7 = \frac{6}{k}$ $9/k - 7 = 6/k$ ?

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How do you solve $\frac{9}{k} - 7 = \frac{6}{k}$ $9/k - 7 = 6/k$ ?

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Answer 1 · 2016-01-23T11:56:51

$k = \frac{3}{7}$ $k = 3/7$

Explanation:

Collect variable terms to 'left hand side' of equation.

ie $\frac{9}{k} - \frac{6}{k} = 7$ $9/k - 6/k = 7$

( the fraction has a common denominator so subtract numerators )

$\frac{3}{k} = \frac{7}{1}$ $3/k = 7/1$

'cross multiply' to obtain 7k = 3

(divide both sides by 7 )

$(cancel(7) k)/cancel(7) = 3/7 rArr k = 3/7$

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How do you solve $\frac{9}{k} - 7 = \frac{6}{k}$ $9/k - 7 = 6/k$ ?

1 Answer

Explanation:

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