Question

How do you solve `9/k - 7 = 6/k`?

Answer 1

`k = 3/7`

Explanation:

Collect variable terms to 'left hand side' of equation.

ie `9/k - 6/k = 7`

( the fraction has a common denominator so subtract numerators )

`3/k = 7/1`

'cross multiply' to obtain 7k = 3

(divide both sides by 7 )

`(cancel(7) k)/cancel(7) = 3/7 rArr k = 3/7`