How do you solve $9^{x - 4} = 81$ $9^(x-4)=81$ ?

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Answer 1 · 2015-02-12T00:36:58

$9^{x - 4} = 81$ $9^(x−4) = 81$ implies $x = 6$ $x = 6$

The only value $p$ $p$ for which $9^{p} = 81$ $9^p = 81$ is $p = 2$ $p = 2$
so
$x - 4 = 2$ $x-4 = 2$ $\to$ $rarr$ $x = 6$ $x=6$

How do you solve 9x−4=819^(x-4)=81?