Question

How do you solve `9v^2-8=0` using the quadratic formula?

Answer 1

`(2sqrt2)/3`

Explanation:

considering quadratic formula having a=9, b=0 and c=-8
Therefore

`v=-b+-sqrt(b^2-4ac)/(2a) = 0+-sqrt(0-4*(9)*(-8))/(2*(9))=+-sqrt288/18 =+-sqrt(2*2*2*2*2*3*3)/18 = (12 sqrt2)/18 = (2sqrt2)/3`