Question

How do you solve `9x^2 - 16 = 0`?

Answer 1

`(3x+4)(3x-4)`

Explanation:

In the general form `(a+b)(a-b)=a^2-b^2`

Treating `9x^2` as `a^2`
`rArr a=3x`
and
treating `16` as `b^2`
`rArr b=4`

`color(green)((3x+4)(3x-4))=9x^2-16`