Question

How do you solve `9x^2 - 21x + 10 = 0`?

Answer 1

By factoring the left side we can get `x=5/3` or `x= 2/3`

Explanation:

Given `9x^2-21x+10`
the left side can be factored to give
`color(white)("XXXX")` `(3x-5)(3x-2)=0`
which implies either
`color(white)("XXXX")` `3x-5 = 0 rArr x = 5/3`
or
`color(white)("XXXX")` `3x-2 =0 rArr x=2/3`