How do you solve 9x-9y=-279x9y=27 and 5x+27=y5x+27=y using substitution?

1 Answer
Feb 9, 2017

See the entire solution process below:

Explanation:

Step 1) Because the second equation is already solved for yy, substitute 5x + 275x+27 for yy in the first equation and solve for xx:

9x - 9y = -279x9y=27 becomes:

9x - 9(5x + 27) = -279x9(5x+27)=27

9x - 45x - 243 = -279x45x243=27

-36x - 243 = -2736x243=27

-36x - 243 + color(red)(243) = -27 + color(red)(243)36x243+243=27+243

-36x - 0 = 21636x0=216

-36x = 21636x=216

(-36x)/color(red)(-36) = 216/color(red)(-36)36x36=21636

(color(red)(cancel(color(black)(-36)))x)/cancel(color(red)(-36)) = -6

x = -6

Step 2) Substitute -6 for x in the second equation and calculate y:

5x + 27 = y becomes:

(5 xx -6) + 27 = y

-30 + 27 = y

-3 = y

y = -3

The solution is x = -6 and y = -3 or (-6, -3)