How do you solve abs(2z -3) = 4z - 1?

1 Answer
Jun 24, 2016

x=3/2

Explanation:

It is equivalent to:

(2z-3>=0 and 2z-3=4z-1) or (2z-3<0 and -2z+3=4z-1)

(z>=3/2 and 2z=-2) or (z<3/2 and 6z=4)

(z>=3/2 and z=-1) or (z<3/2 and z=2/3)

the first condition is impossible, then since 2/3<3/2:

the solution is x=3/2