Question

How do you solve `abs(3x+12)>=42`?

Answer 1

The solutions are `x>=10` and `x<=-18`

Explanation:

We have 2 equations to solve

`3x+12>=42` and `-3x-12>=42`

`3x>(42-12)` and `3x<=(-12-42)`

`3x>=30` and `3x<=-54`

`x>=10` and `x<=-18`