How do you solve and find the extraneous solutions for #2\sqrt{4-3x}+3=0#?
1 Answer
Nov 23, 2014
by subtracting
by dividing by
(Notice that it is now clear that this equation has no real solution since the left-hand side cannot be negative.)
by squaring,
by subtracting
by dividing by
which is its extraneous solution.
I hope that this was helpful.