How do you solve and graph #3x + 8 ≥ 4x #?

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Answer 1 · 2018-07-24T18:48:21

#x <= 8#

#3x + 8 >= 4x#

Subtract #color(blue)(3x)# from both sides:
#3x + 8 quadcolor(blue)(-quad3x) >= 4x quadcolor(blue)(-quad3x)#

#8 >= x#

Therefore,
#x <= 8#

Here's a graph of it on a number line:
enter image source here
(mathwarehouse.com)

The closed circle on #8# means that #8# is one of the solutions (and anything less than it).

Hope this helps!