How do you solve and write the following in interval notation: #-12x + 18 >= -10x + 14#?

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Answer 1 · 2017-02-08T20:48:20

#x in ]-oo;2]#

First you would move the x-terms to the left side of the equation and the numeric terms to the right:

#-12x+10x>=-18+14#

that's

#-2x>=-4#

#2x<=4#

#x<=2#

whose interval notation is:

#x in ]-oo;2]#