First, expand the terms in parenthesis on the right side of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:
#20x + 28 <= color(red)(4)(4x + 5)#
#20x + 28 <= (color(red)(4) xx 4x) + (color(red)(4) xx 5)#
#20x + 28 <= 16x + 20#
Next, subtract #color(red)(28)# and #color(blue)(16x)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:
#20x - color(blue)(16x) + 28 - color(red)(28) <= 16x - color(blue)(16x) + 20 - color(red)(28)#
#(20 - color(blue)(16))x + 0 <= 0 - 8#
#4x <= -8#
Now, divide each side of the inequality by #color(red)(4)# to solve for #x# while keeping the inequality balanced:
#(4x)/color(red)(4) <= -8/color(red)(4)#
#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) <= -2#
#x <= -2#
Or, in interval notation:
#(-oo, -2]#