How do you solve and write the following in interval notation: $|2x + 3| < 11$ ?

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Answer 1 · 2018-04-02T06:38:18

The solution is $x in(-7,4)$

There are $2$ solutions for equation with absolute values.

$|2x+3|<11$

$2x+3<11$ and $-2x-3<11$

$2x<8$ and $2x > -14$

$x<4$ and $x > -7$

The solutions are

$S_1=x in( -oo, 4)$

$S_2=x in (-7,+oo)$

Therefore,

$S=S_1nnS_2$

$=x in ( -7, 4)$

graph{(y-|2x+3|)(y-11)=0 [-5.55, 6.934, -0.245, 5.995]}

How do you solve and write the following in interval notation: |2x + 3| < 11|2x + 3| < 11?