How do you solve and write the following in interval notation: #5(5-2x)≥40-7x#?

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Answer 1 · 2017-04-01T11:53:52

#x in (oo, -5]#

#5(5-2x)≥40-7x#

expand bracket

#25-10x≥40-7x#

subtract 25

#-10x≥15-7x#

add 7x

#-3x≥15#

divide by 3

#-x≥5#

times -1 (and switch inequality sign)

# x le -5#

interval notation:

#implies x in (oo, -5]#