Question

How do you solve and write the following in interval notation: `8- 5x<=23`?

Answer 1

`[-3,+oo)`

Explanation:

`"Isolate " -5x" by subtracting 8 from both sides"`

`cancel(8)cancel(-8)-5x<=23-8`

`rArr-5x<=15`

`"divide both sides by - 5"`

`color(blue)"Note ""when multiplying/dividing an inequality"`
`"by a negative quantity, the inequality sign is "color(red)"reversed"`

`(cancel(-5) x)/cancel(-5)>=15/(-5)larrcolor(red)" reverse sign"`

`rArrx>=-3" is the solution"`

`[-3,+oo)larr" in interval notation"`