Question

How do you solve arccos(cos 2pi)?

Answer 1

`2pi`

Explanation:

arccos or `cos^-1x` and cosx are `color(blue)"inverse functions"`

and `color(red)(|bar(ul(color(white)(a/a)color(black)(f^-1(f(x))=x)color(white)(a/a)|)))`

`rArrarccos(cos(2pi))=2pi`