How do you solve #b/108=7/18#?

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Answer 1 · 2016-11-27T13:58:19

#b = 42#

To isolate and solve for #b#, multiple each side of the equation by #109# and then do the necessary mathematics:

#(108*b)/108 = (7*108)/18#

#(cancel(108)*b)/cancel(108) = (7*108)/18#

#b = (7*6*18)/18#

#b = (7*6*cancel(18))/cancel(18)#

#b = 7*6#

#b = 42#