How do you solve #b/3-6=-2#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer CW Oct 13, 2016 #b=12# Explanation: #b/3-6=-2# 1) Add #6# to both sides : #=> b/3-cancel6+cancel6=-2+6# #=> b/3=4# 2) Multiply both sides with #3# : #=> b/cancel3 *cancel3=4*3# #b=12# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 2962 views around the world You can reuse this answer Creative Commons License