How do you solve by substitution $2 x - y = 23$ $2x-y=23$ and $x - 9 = - 1$ $x-9=-1$ ?

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How do you solve by substitution $2 x - y = 23$ $2x-y=23$ and $x - 9 = - 1$ $x-9=-1$ ?

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Answer 1 · 2018-04-25T00:56:10

We write the second equation $x = 9 - 1 = 8$ $x= 9 -1 = 8$ and substitute into the first: $2 (8) - y = 23$ $2(8) - y = 23$ or $y = 2 (8) - 23 = - 7$ $y = 2(8)-23=-7$ .

Explanation:

Check $x = 8, y = - 7$ $x=8, y=-7$

$2(8) - (-7) = 16 + 7 = 23 quad sqrt$

$8 - 9 = -1 quad sqrt$

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How do you solve by substitution $2 x - y = 23$ $2x-y=23$ and $x - 9 = - 1$ $x-9=-1$ ?

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How do you solve by substitution $2 x - y = 23$ $2x-y=23$ and $x - 9 = - 1$ $x-9=-1$ ?